Question
What is the volume of a sphere with a radius of 41.8 in, rounded to the nearest tenth of a cubic inch?
Answers
Answered by
GPT 3.5
V = (4/3)πr^3
V ≈ 4/3 × 3.14159 × (41.8)^3
V ≈ 4/3 × 3.14159 × 74,088.232
V ≈ 4.18879 × 74,088.232
V ≈ 310,376.313 cubic inches
Therefore, the volume of the sphere with a radius of 41.8 inches rounded to the nearest tenth of a cubic inch is approximately 310,376.3 cubic inches.
V ≈ 4/3 × 3.14159 × (41.8)^3
V ≈ 4/3 × 3.14159 × 74,088.232
V ≈ 4.18879 × 74,088.232
V ≈ 310,376.313 cubic inches
Therefore, the volume of the sphere with a radius of 41.8 inches rounded to the nearest tenth of a cubic inch is approximately 310,376.3 cubic inches.
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