To find the length of the edge of the square base of the Pyramid, we can use the Pythagorean theorem, which states that a² + b² = c², where a and b are the legs of a right triangle and c is the hypotenuse.
Given that the height is 321 ft and the slant height is 436.5 ft, we can calculate the length of the edge of the square base as follows:
Let x be the length of the edge of the square base.
Using the Pythagorean theorem:
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 87460.25
x = √87460.25
x ≈ 295.7 ft
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.7 ft.
The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth.
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11 answers
wrong
My apologies for the mistake. Let's try to calculate it again.
Given that the height is 321 ft and the slant height is 436.5 ft, we can calculate the length of the edge of the square base as follows:
Let x be the length of the edge of the square base.
Using Pythagorean theorem, we have:
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 87460.25
x ≈ √87460.25
x ≈ 295.6 ft
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.6 ft (rounded to the nearest tenth).
Given that the height is 321 ft and the slant height is 436.5 ft, we can calculate the length of the edge of the square base as follows:
Let x be the length of the edge of the square base.
Using Pythagorean theorem, we have:
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 87460.25
x ≈ √87460.25
x ≈ 295.6 ft
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.6 ft (rounded to the nearest tenth).
are you sure
Let's double-check the calculations:
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 190630.25 - 103041
x² = 87589.25
x = √87589.25
x ≈ 295.8 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 295.8 ft when rounded to the nearest tenth. Thank you for your patience.
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 190630.25 - 103041
x² = 87589.25
x = √87589.25
x ≈ 295.8 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 295.8 ft when rounded to the nearest tenth. Thank you for your patience.
bro thats wrong
Apologies for the previous errors. Let's recalculate the length of the edge of the square base:
Given:
Height = 321 ft
Slant height = 436.5 ft
Using the Pythagorean Theorem:
Let x be the length of the edge of the square base.
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 190630.25 - 103041
x² ≈ 87689.25
x ≈ √87689.25
x ≈ 296.1 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 296.1 ft when rounded to the nearest tenth. Thank you for your understanding.
Given:
Height = 321 ft
Slant height = 436.5 ft
Using the Pythagorean Theorem:
Let x be the length of the edge of the square base.
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 190630.25 - 103041
x² ≈ 87689.25
x ≈ √87689.25
x ≈ 296.1 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 296.1 ft when rounded to the nearest tenth. Thank you for your understanding.
wrong bro
Let's try the calculations one more time:
Given:
Height = 321 ft
Slant height = 436.5 ft
Using the Pythagorean Theorem:
Let x be the length of the edge of the square base.
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 190630.25 - 103041
x² = 87589.25
x = √87589.25
x ≈ 295.7 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 295.7 ft when rounded to the nearest tenth. Thank you for your patience.
Given:
Height = 321 ft
Slant height = 436.5 ft
Using the Pythagorean Theorem:
Let x be the length of the edge of the square base.
x² + 321² = 436.5²
x² + 103041 = 190630.25
x² = 190630.25 - 103041
x² = 87589.25
x = √87589.25
x ≈ 295.7 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 295.7 ft when rounded to the nearest tenth. Thank you for your patience.
nope
My apologies for the errors. Let's solve it one more time:
Given:
Height = 321 ft
Slant height = 436.5 ft
Using the Pythagorean Theorem:
Let x be the length of the edge of the square base.
x² + 321² = 436.5²
x² + 103041 = 190622.25
x² = 87392.25
x ≈ √87392.25
x ≈ 295.5 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 295.5 ft when rounded to the nearest tenth.
Given:
Height = 321 ft
Slant height = 436.5 ft
Using the Pythagorean Theorem:
Let x be the length of the edge of the square base.
x² + 321² = 436.5²
x² + 103041 = 190622.25
x² = 87392.25
x ≈ √87392.25
x ≈ 295.5 ft
Therefore, the correct length of the edge of the square base of the Pyramid is approximately 295.5 ft when rounded to the nearest tenth.