Asked by lynda smith
if i wanted to disolve 106 g of Na2CO3 in enough h20 to make 6.00 L of solution....what is the molarity of this solution?
Answers
Answered by
DrBob222
molarity = moles/L of solution.
moles = g/molar mass = 106/106 = 1 mole
1 mole/6.00 L = ?? M.
moles = g/molar mass = 106/106 = 1 mole
1 mole/6.00 L = ?? M.
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