Asked by Anonymous
If you are given a 0.27 g piece of sodium metal to react with water, how many moles of HCl would it take to neutralize the sodium hydroxide produced?
Answers
Answered by
DrBob222
2Na + 2H2O ==> 2NaOH + H2
0.27 g Na = how many moles Na?
0.27/23 = ?? moles Na (I'm using molar mass from my memory so you need to look them up and do them exactly).
How much NaOH is formed?
?? moles Na x (2 moles NaOH/2 moles Na) = ?? moles NaOH.
Now NaOH + HCl ==> H2O + NaCl
So ?? moles NaOH will require ?? (th same) moles HCl.
0.27 g Na = how many moles Na?
0.27/23 = ?? moles Na (I'm using molar mass from my memory so you need to look them up and do them exactly).
How much NaOH is formed?
?? moles Na x (2 moles NaOH/2 moles Na) = ?? moles NaOH.
Now NaOH + HCl ==> H2O + NaCl
So ?? moles NaOH will require ?? (th same) moles HCl.
Answered by
Anonymous
3
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