g^2+4g-32=0

Answer 1

To solve this quadratic equation, we can use the quadratic formula:

g = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a = 1, b = 4, and c = -32.

Plugging these values into the quadratic formula, we get:

g = (-4 ± √(4^2 - 4*1*(-32))) / 2*1
g = (-4 ± √(16 + 128)) / 2
g = (-4 ± √144) / 2
g = (-4 ± 12) / 2

Now we have two possible solutions for g:

g = (-4 + 12) / 2 = 8 / 2 = 4

g = (-4 - 12) / 2 = -16 / 2 = -8

Therefore, the solutions to the quadratic equation g^2 + 4g - 32 = 0 are g = 4 and g = -8.