Asked by Christie
If I have 2- 1/2 reactions that are- O2(g)+4H(aq)+4e- -------2H2O and CyFe3+(aq) +e---------CyFe2+(aq) How do I determine the # of electrons transfered? In addition, if the electrons are on different sides of the equations how would I then determine the # being transfered? Thank you for looking at this!
Answers
Answered by
DrBob222
For #1, the equation tells you 4 electrons are transferred and 1 electron transferred for #2.
To balance the two half reactions for a complete reaction, you will multiply half reaction 1 by 1 and half reaction 2 by 4, then add the two half reactions/equations. That will give you 4e on the left side of the arrow and 4e on the right side of the arrow which tells you (a) the electrons cancel and (b) there are 4 electrons transferred in the total reaction.
To balance the two half reactions for a complete reaction, you will multiply half reaction 1 by 1 and half reaction 2 by 4, then add the two half reactions/equations. That will give you 4e on the left side of the arrow and 4e on the right side of the arrow which tells you (a) the electrons cancel and (b) there are 4 electrons transferred in the total reaction.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.