Asked by Public High School Pre Calculus HH
                Ok I do not know how to do this problem.  I know that csc is simply sin^-1
sin (- pi/12) csc ( (37 pi)/12
ok now I know this also
sin (- pi /12 ) = - sin ( pi/12)
not really sure how that helps
I don't know were to go from here
( - sin (pi/12) )/(sin ( (25 pi)/12 ) )
            
            
        sin (- pi/12) csc ( (37 pi)/12
ok now I know this also
sin (- pi /12 ) = - sin ( pi/12)
not really sure how that helps
I don't know were to go from here
( - sin (pi/12) )/(sin ( (25 pi)/12 ) )
Answers
                    Answered by
            bobpursley
            
    I thought I answered this.
Remember sin Theta=sin(theta+2PI)
and, remember that sin(-theta)=-sinTheta
so
Sin(-PI/12)=-sin(PI/12)
and lastly, sin(theta)=-sin(theta+PI)
Now, to the task
sin(-PI/12)=-sin(PI/12)= + sin(PI/12+PI)
= sin(13PI/12)=sin(13PI/12+2PI)
= sin(13PI/12+24pi/12)=sin 37PI/12
Now you have
sin(37PI/12)*csc(37pi/12)=1
    
Remember sin Theta=sin(theta+2PI)
and, remember that sin(-theta)=-sinTheta
so
Sin(-PI/12)=-sin(PI/12)
and lastly, sin(theta)=-sin(theta+PI)
Now, to the task
sin(-PI/12)=-sin(PI/12)= + sin(PI/12+PI)
= sin(13PI/12)=sin(13PI/12+2PI)
= sin(13PI/12+24pi/12)=sin 37PI/12
Now you have
sin(37PI/12)*csc(37pi/12)=1
                    Answered by
            READ
            
    Why did you take the negative sign out?
sin(-PI/12)=-sin(PI/12)
I understand this
why are we adding pi to the denomenator
I udner stand that sin (theta) = sin (theta + 2pi)
= + sin(PI/12+PI)
I don't understand that
= sin(13PI/12)
how did we get thirteen ontop?
=sin(13PI/12+2PI)
I understood that
= sin(13PI/12+24pi/12)
so you just rewrote 2pi in therms of a twelth (24pi)/12 makes sense
=sin 37PI/12
ok simplified it
ok so if you can explain the steps i don't understand that would be great thanks!!!!
    
sin(-PI/12)=-sin(PI/12)
I understand this
why are we adding pi to the denomenator
I udner stand that sin (theta) = sin (theta + 2pi)
= + sin(PI/12+PI)
I don't understand that
= sin(13PI/12)
how did we get thirteen ontop?
=sin(13PI/12+2PI)
I understood that
= sin(13PI/12+24pi/12)
so you just rewrote 2pi in therms of a twelth (24pi)/12 makes sense
=sin 37PI/12
ok simplified it
ok so if you can explain the steps i don't understand that would be great thanks!!!!
                    Answered by
            bobpursley
            
    sin(PI/12 + PI) is not adding it to the denominator, If I wanted to add it to the denominator..
Sin(PI/(12+PI))
So
Sin(PI/12 + PI)=sin (PI/12 + 12PI/12)=
sin(13PI/12)
go back and reread what I did.
    
Sin(PI/(12+PI))
So
Sin(PI/12 + PI)=sin (PI/12 + 12PI/12)=
sin(13PI/12)
go back and reread what I did.
                    Answered by
            PLEASE READ
            
    ok then everything makes sense you just added pi to make it positive and then everything else makes perfect sense but allows you just to add pi to make it positive?
    
                    Answered by
            PLEASE READ
            
    will I do that on my calculator and get the same answer so I guess it's some kind of property of sin...???
    
                    Answered by
            PLEASE READ
            
    so then I can state this?
for sin (theta)
I can add pi to theta and still get the same answer??? this would appear to be true
does this also hold true for cosine and tangent?
    
for sin (theta)
I can add pi to theta and still get the same answer??? this would appear to be true
does this also hold true for cosine and tangent?
                    Answered by
            PLEASE READ
            
    So then
sin - theta + pi = sin theta
cos - theta + pi = cos -theta
ok then I can just simply add pi to it to change it's sign (positive or negative) just like I could with anything without changing it's value????
so we can just simply add pi to theta because it dosen't change its value but it change it's sign which we can do because...
    
sin - theta + pi = sin theta
cos - theta + pi = cos -theta
ok then I can just simply add pi to it to change it's sign (positive or negative) just like I could with anything without changing it's value????
so we can just simply add pi to theta because it dosen't change its value but it change it's sign which we can do because...
                    Answered by
            So What Did I do Wrong
            
    I put this into my calculator and get negative one not positive one
(sin(-pi/12))(sin((25pi)/12))^-1
    
(sin(-pi/12))(sin((25pi)/12))^-1
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