To solve this system of equations, we can substitute the value of Y from the first equation into the second equation.
Given:
Y = 2 + 3X
4X - 3Y = -16
Substitute the value of Y:
4X - 3(2 + 3X) = -16
4X - 6 - 9X = -16
-5X - 6 = -16
-5X = -16 + 6
-5X = -10
X = -10 / -5
X = 2
Now that we have found the value of X, we can substitute it back into the first equation to find the value of Y:
Y = 2 + 3(2)
Y = 2 + 6
Y = 8
Therefore, the solution to the system of equations is:
X = 2
Y = 8
Solve the system of equations
Y equals 2+ 3X
4X minus 3Y equals -16
1 answer