To solve this system of equations, we can use either the substitution method or the elimination method.
Let's use the substitution method:
From the second equation, we can solve for x in terms of y:
x = 22 + 6y
Now we substitute x = 22 + 6y into the first equation:
5(22 + 6y) + 2y = 14
110 + 30y + 2y = 14
32y = -96
y = -3
Now substitute y = -3 back into the second equation to solve for x:
x - 6(-3) = 22
x + 18 = 22
x = 4
Therefore, the solution to the system of equations is x = 4 and y = -3.
Solve the system of equations
5x+2y=14
X-6y=22
1 answer