To solve this system of equations, we can substitute the second equation into the first equation and solve for x.
8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
-4x - 30 = -22
-4x = 8
x = -2
Now that we have found the value of x, we can substitute it back into the second equation to solve for y.
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.
Solve the system of equations
8x-3y=-22
Y=10+4x
1 answer