Let's represent the number as x.
According to the given information, we can write the equation as:
x^2 - 4 = 3x
Rearranging the equation, we get:
x^2 - 3x - 4 = 0
Now, we need to solve this quadratic equation to find the positive solution. Factoring the equation, we get:
(x - 4)(x + 1) = 0
Setting each factor to zero, we get the possible solutions:
x - 4 = 0 or x + 1 = 0
Therefore, x = 4 or x = -1.
Since we're looking for the positive solution, the answer is x = 4.
The difference of the square of a number and 4 is equal to 3 times that number. Find the positive solution.
1 answer