A 10cm times 10cm times 10cm wood block with a density of 700kg/m^{3} floats in water. What is the distance from the top of the block to the water if the water is fresh? and If it's seawater?

Answer 1

figure the weight:
weight= density*volume*g

then the weight of the water displaced is equal to that..

weight=densitywater*g*10cm*10cm*depth
solve for depth.

Answer 2

weight= density*volume*g
weight=700*10cm*9.81
weight=68670

weight=densitywater*g*10cm*10cm*depth
68670=700*9.81*10cm*10cm*d
d=.1
it isnt right:-(

Answer 3

the volume is not 10 cm. It is 1000cm^3

Answer 4

oh ok
weight= density*volume*g
weight=700*1000cm*9.81
weight=6867000

weight=densitywater*g*10cm*10cm*depth
6867000=700*9.81*10cm*10cm*d
d=10
still didn't work,am i missing something?