Asked by ana

A 10cm times 10cm times 10cm wood block with a density of 700kg/m^{3} floats in water. What is the distance from the top of the block to the water if the water is fresh? and If it's seawater?
Answered by bobpursley
figure the weight:
weight= density*volume*g

then the weight of the water displaced is equal to that..

weight=densitywater*g*10cm*10cm*depth
solve for depth.

Answered by ana
weight= density*volume*g
weight=700*10cm*9.81
weight=68670

weight=densitywater*g*10cm*10cm*depth
68670=700*9.81*10cm*10cm*d
d=.1
it isnt right:-(
Answered by bobpursley
the volume is not 10 cm. It is 1000cm^3
Answered by ana
oh ok
weight= density*volume*g
weight=700*1000cm*9.81
weight=6867000

weight=densitywater*g*10cm*10cm*depth
6867000=700*9.81*10cm*10cm*d
d=10
still didn't work,am i missing something?
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