For the square pyramid, the lateral edge length, e , is 25 in., and the slant height, s , is 24 in. Find the height of the pyramid, h . Round the answer to the nearest whole number. Hint: Before finding the length of h , you will first need to find the length of rr . (1 point)

Answer 1

Using the Pythagorean theorem, we can find the length of the base edge, r:

r^2 + (e/2)^2 = s^2
r^2 + (25/2)^2 = 24^2
r^2 + 12.5^2 = 576
r^2 + 156.25 = 576
r^2 = 576 - 156.25
r^2 = 419.75
r ≈ √419.75
r ≈ 20.49 in

Now, we can find the height, h:

h^2 = s^2 - r^2
h^2 = 24^2 - 20.49^2
h^2 = 576 - 419.75
h^2 = 156.25
h ≈ √156.25
h ≈ 12.5 in

Therefore, the height of the pyramid, h, is approximately 12.5 inches.

Answer 2

wrong

Answer 3

I apologize for the mistake. Let's try this again:

Using the Pythagorean theorem, we can find the length of the base edge, r:

r^2 + (e/2)^2 = s^2
r^2 + (25/2)^2 = 24^2
r^2 + 12.5^2 = 576
r^2 + 156.25 = 576
r^2 = 576 - 156.25
r^2 = 419.75
r ≈ √419.75
r ≈ 20.49 in

Now, we can find the height, h:

h^2 = s^2 - r^2
h^2 = 24^2 - 20.49^2
h^2 = 576 - 419.75
h^2 = 156.25
h ≈ √156.25
h ≈ 12.5

Apologies for the error, it seems that the height of the pyramid, h, is indeed 12 inches.

Answer 4

doubl check and give me the correct answer

Answer 5

Let's reevaluate the calculations for the height of the pyramid:

Given:
Lateral edge length, e = 25 in
Slant height, s = 24 in

We already calculated the base edge length r to be approximately 20.49 in.

Now, let's find the height, h:

h^2 = s^2 - r^2
h^2 = 24^2 - 20.49^2
h^2 = 576 - 419.9401
h^2 = 156.0599
h ≈ √156.0599
h ≈ 12.49 in

Therefore, upon double-checking, the correct height of the pyramid, h, is approximately 12.49 inches. Thank you for bringing that to my attention.