Asked by THOMAS HARDY
What value of p are
2p-1,7 and 3P three consecutive terms of ARITHMETIC PROGRESSION
2p-1,7 and 3P three consecutive terms of ARITHMETIC PROGRESSION
Answers
Answered by
tchrwill
What value of p are 2p-1, 7 and 3p three consecutive terms of an ARITHMETIC PROGRESSION?
Letting a = the common difference, we can write
1--(7 - a) = 2P - 1 and
2--(7 + a = 3p
Adding yields 14 = 5p - 1 from which p = 3 making the 3 terms 5, 7 and 9.
Letting a = the common difference, we can write
1--(7 - a) = 2P - 1 and
2--(7 + a = 3p
Adding yields 14 = 5p - 1 from which p = 3 making the 3 terms 5, 7 and 9.
Answered by
ty
figer math for 2nd grade
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