First we need to substitute (x-3) into the function f(x):
f(x) = (x-3)^2 - 12
Then, we need to multiply this function by 2:
2f(x) = 2[(x-3)^2 - 12]
To simplify the expression further, we can expand the squared term and distribute the 2:
2f(x) = 2(x^2 - 6x + 9 - 12)
= 2x^2 - 12x + 18 - 24
= 2x^2 - 12x - 6
Therefore, the expression 2f(x-3) is 2x^2 - 12x - 6.
When using the order of operations to transform f (x) = x^2 -12 to 2f (x-3) what needs to be completed first
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