To determine the tide depth at 10:00 on January 6th, we need to substitute t = 10 into the polynomial function given as:
f(10) = 0.1(10^3) - 1.9(10^2) + 13(10) - 4.6
Calculating this expression, we get:
f(10) = 0.1(1000) - 1.9(100) + 13(10) - 4.6
f(10) = 100 - 190 + 130 - 4.6
f(10) = 36.4
Therefore, the tide depth in Deep Cove, British Columbia at 10:00 on January 6th, 2011 is 36.4 metres.
The tide depth in Deep Cove, British Columbia, from 04:00 to 15:00 on January 6, 2011, is shown by the following polynomial function:
Where f(t) is the tide depth in metres and t is the number of hours after midnight.
Use the calculator features to determine the tide depth at 10:00 on January 6th.
1 answer
1 answer