1.2×10^3 - 1200
1.2×10^−4 - 0.00012
1.2×10^2 - 120
1.2×10^−2 - 0.012
1.2 - 1.2
0.00012 - 0.00012
Match the number in scientific notation to the same number in standard notation.(5 points)
1.2×10^3
1.2×10^−4
1.2×10^2
1.2×10^−2
1.2×10^0
1.2
120
1200
0.00012
12
0.0012
0
0.012
0.000012
5 answers
1.2×10^0
Match the number in scientific notation to the same number in standard notation.(5 points)
1.2
120
1200
0.00012
12
0.0012
0
0.012
0.000012
Match the number in scientific notation to the same number in standard notation.(5 points)
1.2
120
1200
0.00012
12
0.0012
0
0.012
0.000012
1.2×10^0 - 1.2
120 - 120
1200 - 1200
0.00012 - 0.00012
12 - 12
0.0012 - 0.0012
0 - 0
0.012 - 0.012
0.000012 - 0.000012
120 - 120
1200 - 1200
0.00012 - 0.00012
12 - 12
0.0012 - 0.0012
0 - 0
0.012 - 0.012
0.000012 - 0.000012
Which symbol would you use to correctly compare? Draw a numberline to help you. 6.2×10−3 and 0 and 1 (1 point)
6.2 x 10^-3 > 0 and 6.2 10^-3 > 1
6.2 x 10^-3 < 0 and 6.2 10^-3 > 1
0 < 6.2 x 10^-3 < 1
6.2 x 10^-3 < 0 and 6.2 10^-3 < 1
6.2 x 10^-3 > 0 and 6.2 10^-3 > 1
6.2 x 10^-3 < 0 and 6.2 10^-3 > 1
0 < 6.2 x 10^-3 < 1
6.2 x 10^-3 < 0 and 6.2 10^-3 < 1
To compare 6.2×10^-3 with 0 and 1, you can represent them on a number line.
Divide the number line into three sections: one for 0, one for 1, and one for 6.2×10^-3.
0 would be at the left end of the number line, followed by 6.2×10^-3 (which is greater than 0 but less than 1), and finally 1 at the right end of the number line.
Therefore, the correct comparison is:
0 < 6.2 x 10^-3 < 1.
Divide the number line into three sections: one for 0, one for 1, and one for 6.2×10^-3.
0 would be at the left end of the number line, followed by 6.2×10^-3 (which is greater than 0 but less than 1), and finally 1 at the right end of the number line.
Therefore, the correct comparison is:
0 < 6.2 x 10^-3 < 1.
3 answers