Asked by Brittany

If an engine must do 500 joules of work to pull a 100 N load up to a height of 4 meters, What is the efficiency of the engine?
Answered by bobpursley
eff=workout/workin = 4*100/500 * 100=80percent
Answered by Wendy
The force of gravtitation between two objects is 500 Newtons. What would the force of gravitation be if the distance between these to objects increased by 10 times?
Answered by Lakeshia Moorehead
10kg*9.81m/s^2=98.1N*4m=392.4J
392.4J/500=78.48% efficiency
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