Question
Calculate the volume in milliliters of a 0.217 mol/L potassium permanganate solution that contains 25.0 g of potassium permanganate (KMnO4). Be sure your answer has the correct number of significant digits.
Answers
Answered by
GPT 3.5
To calculate the volume of the solution, we can use the formula:
Volume = (mass of solute (g) / molar mass of solute (g/mol)) / concentration (mol/L)
First, let's find the molar mass of potassium permanganate (KMnO4):
K: 1 mol x 39.10 g/mol = 39.10 g/mol
Mn: 1 mol x 54.94 g/mol = 54.94 g/mol
O: 4 mol x 16.00 g/mol = 64.00 g/mol
Total molar mass = 39.10 + 54.94 + 64.00 = 158.04 g/mol
Now we can substitute the given values into the formula:
Volume = (25.0 g / 158.04 g/mol) / 0.217 mol/L
Volume = (0.1583 mol) / 0.217 mol/L
Volume = 0.7290 L
Lastly, we need to convert the volume from liters to milliliters:
Volume (mL) = 0.7290 L x 1000 mL/L = 729 mL
Therefore, the volume of the potassium permanganate solution is 729 mL.
Volume = (mass of solute (g) / molar mass of solute (g/mol)) / concentration (mol/L)
First, let's find the molar mass of potassium permanganate (KMnO4):
K: 1 mol x 39.10 g/mol = 39.10 g/mol
Mn: 1 mol x 54.94 g/mol = 54.94 g/mol
O: 4 mol x 16.00 g/mol = 64.00 g/mol
Total molar mass = 39.10 + 54.94 + 64.00 = 158.04 g/mol
Now we can substitute the given values into the formula:
Volume = (25.0 g / 158.04 g/mol) / 0.217 mol/L
Volume = (0.1583 mol) / 0.217 mol/L
Volume = 0.7290 L
Lastly, we need to convert the volume from liters to milliliters:
Volume (mL) = 0.7290 L x 1000 mL/L = 729 mL
Therefore, the volume of the potassium permanganate solution is 729 mL.