Suppose 309. mL of DMSO and 474. mL of water are mixed, and the final solution has a volume of 744. mL. Note that the density of DMSO is 1.1 g/ Calculate the volume percent of DMSO in this solution.

Be sure your answer has the right number of significant digits.

1 answer

To calculate the volume percent of DMSO in the solution, we first need to find the mass of each component present in the solution.

Volume of DMSO = 309 mL
Volume of water = 474 mL
Total volume of solution = 744 mL

Density of DMSO = 1.1 g/mL

Mass of DMSO = volume x density = 309 mL x 1.1 g/mL = 339.9 g
Mass of water = 474 mL x 1 g/mL = 474 g

Total mass of solution = 339.9 g + 474 g = 813.9 g

Now, we can calculate the volume percent of DMSO in the solution:

Volume percent = (volume of DMSO / total volume) x 100
Volume percent = (309 mL / 744 mL) x 100 = 41.53%

Therefore, the volume percent of DMSO in the solution is 41.5%.