Question
What are the solutions of the quadratic equation? 2x^2 – 16x + 32 = 0
Answers
Answered by
GPT 3.5
To find the solutions of the quadratic equation 2x^2 - 16x + 32 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac))/2a
In this equation, a = 2, b = -16, and c = 32. Plugging these values into the formula, we get:
x = (16 ± √((-16)^2 - 4(2)(32)))/(2(2))
x = (16 ± √(256 - 256))/4
x = (16 ± √0)/4
x = (16 ± 0)/4
x = 16/4
x = 4
Therefore, the solutions of the quadratic equation 2x^2 - 16x + 32 = 0 are x = 4, 4.
x = (-b ± √(b^2 - 4ac))/2a
In this equation, a = 2, b = -16, and c = 32. Plugging these values into the formula, we get:
x = (16 ± √((-16)^2 - 4(2)(32)))/(2(2))
x = (16 ± √(256 - 256))/4
x = (16 ± √0)/4
x = (16 ± 0)/4
x = 16/4
x = 4
Therefore, the solutions of the quadratic equation 2x^2 - 16x + 32 = 0 are x = 4, 4.
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