The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours. What was the total kilowatt-hours of electricity used during these two years? (2 points)

Question

(6.3 × 10^9) × (4.3 × 10^11) = 25.929 × 10^20 = 2.6 × 10^19.
(6.3 × 10^9) + (4.3 × 10^11) = 0.063 × 10^11 + (4.3 × 10^11) = 4.363 × 10^11
(6.3 × 10^9) + (4.3 × 10^11) = 10.33 × 10^20 = 1.033 × 10^19
(6.3 × 10^9) × (4.3 × 10^11) = 25.929 × 10^2 = 2.6 × 10^1

Answer 1

The correct answer is: (6.03 × 10^9) + (4.3 × 10^11) = 4.363 × 10^11.

Therefore, the total kilowatt-hours of electricity used during the two years was 4.363 × 10^11 kilowatt-hours.

Answer 2

The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours. How many times more was the electricity used in 1950 than 1902? Express your answer in Scientific Notation. (2 points)
Add coefficients and add powers: 10.33×10^20
Divide coefficients and subtract powers: 1.4 x 10^2
Multiply coefficients and add powers: 2.6×10^21
Divide coefficients and subtract powers: 7.13×10^1
Subtract coefficients and divide powers: 1.73×10^2

Answer 3

To find out how many times more electricity was used in 1950 than in 1902, we need to divide the amount used in 1950 by the amount used in 1902.

(4.3 × 10^11) / (6.03 × 10^9) = (4.3 / 6.03) × 10^(11-9) = 0.712852 × 10^2 = 7.12852 x 10^0 = 7.13 x 10^0

Therefore, the amount of electricity used in 1950 was 7.13 times more than the amount used in 1902.