Use the image to answer the question.

An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the 3 rectangles is 1 centimeter. The length of the outer rectangles is 2.5 centimeters. The length of the middle rectangle is 3 centimeters. Two right triangles adjoin the middle rectangle on the top and bottom along the 3 centimeter side, with their perpendicular height measuring 2 centimeters. A right angle is shown where the perpendicular height intersects with the triangle base.

What is the surface area of the triangular prism whose net is shown?

(1 point)
Responses

2.48 cm2
2.48 cm squared

14 cm2
14 cm squared

8 cm2
8 cm squared

6 cm2
6 cm squared
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1 answer

The surface area of the triangular prism can be calculated by finding the area of each individual rectangle and triangle on the net and adding them together.

Area of each rectangle:
2.5cm (length) x 1cm (width) = 2.5 cm²
3cm (length) x 1cm (width) = 3 cm²
2.5cm (length) x 1cm (width) = 2.5 cm²

Area of each triangle:
1/2 x 3cm (base) x 2cm (height) = 3 cm²
1/2 x 3cm (base) x 2cm (height) = 3 cm²

Total surface area:
2.5 cm² + 3 cm² + 2.5 cm² + 3 cm² + 3 cm² = 14 cm²

Therefore, the surface area of the triangular prism is 14 cm².