Question

the quadratic equation 6x^2-x-15=0 in factored form is:
(3x-5)(2x+3)=0
(6x+5)(x-1)=0
(3x-5)(2x-3)=0
(6x+5)(2x-3)=0

Answer 1

which results in the solutions x=
-6/5
5/3
5
-5

and x=
-3
1
3
-3/2

Answer 2

which of the equations has one solution that is 5/4? Select all that apply
4x^2+3x=-10
4x^2+x+5=0
4x^2+3x-10=0
4x^2-x=5
4x^2-13x+10=0

Answer 3

there is more than one answer

Answer 4

so is 4x^2+3x-10=0 still an answer

Answer 5

(3x-5)(2x+3)=0

Answer 6

The solutions are x = 5/3 and x = -3/2.

Answer 7

The equation that has one solution that is 5/4 is:
4x^2+3x-10=0.
In this equation, the solution x = 5/4.

Answer 8

I apologize for the oversight. The equations that have one solution that is 5/4 are:
1. 4x^2+3x=-10
2. 4x^2-13x+10=0

In both of these equations, x = 5/4 is a valid solution. Thank you for pointing out the error.

Answer 9

Apologies for the confusion earlier. Let's revisit the responses:

The equations that have one solution that is 5/4 are:
1. 4x^2+3x=-10
2. 4x^2-13x+10=0

So, 4x^2+3x=-10 is indeed one of the equations that have one solution at x = 5/4.