Question

A 10cm times 10cm times 10cm block of steel (rho _steel= 7900kg/m^{3}) is suspended from a spring scale. The scale is in newtons.
Part A:What is the scale reading if the block is in air?
Part B:What is the scale reading after the block has been lowered into a beaker of oil (rho_oil=900kg/m^3) and is completely submerged?

Answer 1

The volume of the block is .1^3 meters^3

weightinAir=density*volume*g

Now, in oil, buoyancy subtracts..
weight=weight in air-weight of oil displaced.

figure the weight of oil displaced the same way as above

Answer 2

Thanks, It works...