To solve this system of equations by elimination, we can multiply the first equation by 2 to make the coefficients of x cancel out when added to the second equation:
-4x - 8y = -20 (multiply by 2)
8x + 3y = 1
-8x - 16y = -40
8x + 3y = 1
Now add the two equations together to eliminate x:
-13y = -39
y = 3
Now substitute y = 3 back into either of the original equations to solve for x. Let's use the first equation:
-4x - 8(3) = -20
-4x - 24 = -20
-4x = 4
x = -1
Therefore, the solution to the system of equations is x = -1 and y = 3.
solve the following system of equations by elimination
-4x - 8y = -20
8x + 3y = 1
1 answer