For a short part of its trajectory (Δx=1,074 m

Question

), the shuttlecock moves in an approximately straight line over a period of Δt=0,02 s
. The shuttlecock has a mass of m=5 g
.

Ignore the effects of air resistance. Also ignore the effects of gravity on the shuttlecock during this short part of its trajectory.

1.Calculate the magnitude of the average velocity (vavg
) of the shuttlecock over this period of its trajectory.
2. Calculate the magnitude of the average momentum (pavg
) of the shuttlecock over this period of its trajectory.

Answer 1

1. To calculate the magnitude of the average velocity (vavg), we use the formula:

vavg = Δx / Δt

Plugging in the values we have:

vavg = 1,074 m / 0.02 s
vavg = 53,700 m/s

Therefore, the magnitude of the average velocity of the shuttlecock over this period of its trajectory is 53,700 m/s.

2. To calculate the magnitude of the average momentum (pavg) of the shuttlecock, we use the formula:

pavg = m * vavg

Plugging in the values we have:

pavg = 0.005 kg * 53,700 m/s
pavg = 268.5 kg*m/s

Therefore, the magnitude of the average momentum of the shuttlecock over this period of its trajectory is 268.5 kg*m/s.