Asked by Murajabash
Did I do this right?
Find the vertex, the x intercepts and y intercepts.
f(x)=(x-2)^2-4
Vertex: 2,4
X intercepts: 0,0 4,0
Y intercepts: I didn't know how to get these. Could you explain?
Find the vertex, the x intercepts and y intercepts.
f(x)=(x-2)^2-4
Vertex: 2,4
X intercepts: 0,0 4,0
Y intercepts: I didn't know how to get these. Could you explain?
Answers
Answered by
bobpursley
Isn't the vertex at 0,-4?
y intercepts are when x is zero
y=-2^2-4 or 0
x intercepts are when y is zero
0=(x-2)^2 -4
x-2=+-2
x=0, 4
y intercepts are when x is zero
y=-2^2-4 or 0
x intercepts are when y is zero
0=(x-2)^2 -4
x-2=+-2
x=0, 4
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