Asked by Sasha
a 145g baseball is dropped from a tree 13.0m above the ground. with what is the velocity of the baseball at the ground after it falls 13.0m? B. If it actually hits the ground with a speed of 8.0o m/s, what is the average force of air resistance exerted on it?
Answers
Answered by
drwls
Use conservation of energy to calculate the velocity at the ground with no friction.
V = sqrt (2 g H) = 15.97 m/s
If there is a lower velocity of 8.0 m/s, which is about 1/2 of the frictionless value, than about 3/4 of the available potential energy has been lost to friction.
Friction energy loss = (3/4)*M g H = ?
For the average force, solve
(friction energy loss)= (average force) x (13.0 m)
V = sqrt (2 g H) = 15.97 m/s
If there is a lower velocity of 8.0 m/s, which is about 1/2 of the frictionless value, than about 3/4 of the available potential energy has been lost to friction.
Friction energy loss = (3/4)*M g H = ?
For the average force, solve
(friction energy loss)= (average force) x (13.0 m)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.