A ball is hit over the fence at a 45 degree angle. The fence is 98 meters away. At what velocity does the ball leave the bat?

Answer 1

Horizontal Range = (V^2/g)*sin(2A)= 98 m
(sin 2A = 1)

V^2 = 98 * 9.81 m^2/s^2

Solve for V

This assumes that the height of the fence is 0, which is rather unlikely. A fence height should have been specified.