Question

Calculate the value of OHT from the given

Note: The ion product of water = 1.0 x 10"14

Part 1 of 2

H30+

in each solution and label the solution as acidic, basic, or neutral.

M

(Choose one) V

10

X

Be sure your answer has the correct number of significant figures.

[H30+]=10-13 M

[OH-]=

This solution is

Answer 1

acidic.

To calculate the value of [OH-], we can use the ion product of water:

[H3O+][OH-] = 1.0 x 10^(-14)

Since we know the concentration of [H3O+] is 10^-13 M, we can substitute this value into the equation:

(10^-13)([OH-]) = 1.0 x 10^(-14)

[OH-] = (1.0 x 10^(-14)) / (10^-13)
[OH-] = 1.0 x 10^(-14) / 10^-13
[OH-] = 1.0 x 10^-1
[OH-] = 0.1 M

Therefore, the concentration of [OH-] in the solution is 0.1 M and the solution is acidic.