Asked by Jack

Suppose David Ortiz hits a home run which travels 361. feet (110. m). Assuming it left the bat at 50.°, how fast was it hit?
Answered by bobpursley
separate the initial velocity into vertical and horizontal components.

Viv=Vsin50
Vih=Vcos50
horizontaldistance=Vih*t
solve for t.
Now,
you know the vertical distance..
Hf=Hi+Viv*t-1/2 g t^2
where Viv=Vsin50
solve for V.
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