Question

2, what are zeros of a polynomial f(x) =42+x-x^2

Answer 1

To find the zeros of a polynomial, you set the polynomial equal to zero and then solve for x.

So for the polynomial f(x) = 42 + x - x^2, we set it equal to zero:

42 + x - x^2 = 0

Now we can rearrange the equation to get it in standard form:

x^2 - x - 42 = 0

Now, we can factor the quadratic equation:

(x - 7)(x + 6) = 0

Setting each factor to zero and solving for x, we get:

x - 7 = 0
x = 7

and

x + 6 = 0
x = -6

Therefore, the zeros of the polynomial f(x) = 42 + x - x^2 are x = 7 and x = -6.