Asked by natalie
How many kg of pure salt must be added to 8 kg of a 30% solution to obtain a 35% soltution? Round to the nearest tenth.
Answers
Answered by
drwls
Let x be the number of kg added. the amount of NaCl initially present is
30% x 8 = 2.40 kg .
For the stronger mixture,
x + 2.4 = 0.35 (8.0 + x)= 2.8 + 0.35 x
0.65 x = 0.4
Solve for x
30% x 8 = 2.40 kg .
For the stronger mixture,
x + 2.4 = 0.35 (8.0 + x)= 2.8 + 0.35 x
0.65 x = 0.4
Solve for x
Answered by
bobpursley
well consider the original solution.
IT has .3*8kg of salt in it, and .7*8kg water.
Newsalt+oldsalt=.35(8kg +newsalt)
.65Newsalt=.35*8 - .3*8=.4kg
solve for Newsalt.
IT has .3*8kg of salt in it, and .7*8kg water.
Newsalt+oldsalt=.35(8kg +newsalt)
.65Newsalt=.35*8 - .3*8=.4kg
solve for Newsalt.
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