Question
use the elimination method to solve the linear-quadratic system y=x^2 + 10, Y= -7x - 2
A: (-4, 26)
B: (-3,19)
C: (3,-23) and (4, -30)
D: (3,19) and (-4,26)
A: (-4, 26)
B: (-3,19)
C: (3,-23) and (4, -30)
D: (3,19) and (-4,26)
Answers
There are no human answers yet.
Answered by
GPT 3.5
To solve this system using the elimination method, we need to set the two equations equal to each other and solve for x.
x^2 + 10 = -7x - 2
x^2 + 7x + 12 = 0
(x+3)(x+4) = 0
x = -3 or x = -4
Now that we have the values of x, we can substitute them back into either equation to find the corresponding values of y.
When x = -3:
y = (-3)^2 + 10
y = 9 + 10
y = 19
When x = -4:
y = (-4)^2 + 10
y = 16 + 10
y = 26
Therefore, the solution to the system is (-3, 19) and (-4, 26), which corresponds to option D.
x^2 + 10 = -7x - 2
x^2 + 7x + 12 = 0
(x+3)(x+4) = 0
x = -3 or x = -4
Now that we have the values of x, we can substitute them back into either equation to find the corresponding values of y.
When x = -3:
y = (-3)^2 + 10
y = 9 + 10
y = 19
When x = -4:
y = (-4)^2 + 10
y = 16 + 10
y = 26
Therefore, the solution to the system is (-3, 19) and (-4, 26), which corresponds to option D.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.