Asked by Anonymous
How do you do this problem Multiply. 1B7twelve x 29twelve
Answers
Answered by
Reiny
I would change it to base 10, do the multiplication , then convert back to base 12
1B7 = 12^2 + 1(12) + 7 = 286
29 = 2(12) + 9 = 33
289*33 = 9537
9537 = 5(12)^3 + 897
= 5(12)^3 + 6(12)^2 + 33
= 5(12)^3 + 6(12)^2 + 2(12) + 9
= 5629<sub>12</sub>
1B7 = 12^2 + 1(12) + 7 = 286
29 = 2(12) + 9 = 33
289*33 = 9537
9537 = 5(12)^3 + 897
= 5(12)^3 + 6(12)^2 + 33
= 5(12)^3 + 6(12)^2 + 2(12) + 9
= 5629<sub>12</sub>
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