Question

What is the vertex of the graph of this equation y = -4x²-16x-127

A. (- 2, 4)

B. (2, - 4)

C. (2, 4)

D. (- 2, - 4)

Answer 1

To find the vertex of the graph of the equation y = -4x² - 16x - 127, we can use the formula for the vertex of a parabola of the form y = ax² + bx + c, where the vertex is given by the point (-b/2a, f(-b/2a)).

In this case, a = -4 and b = -16. Plugging these values into the formula, we get:

-(-16) / 2(-4) = 16 / -8 = -2

Now substitute x = -2 back into the original equation to find the corresponding y-value:

y = -4(-2)² - 16(-2) - 127
y = -4(4) + 32 - 127
y = -16 + 32 - 127
y = -16 - 95
y = -111

Therefore, the vertex of the graph of the equation y = -4x² - 16x - 127 is (-2, -111).

D. (-2, -111)