Asked by Jeannie
Compare the bond enthalpies of the nitrogen-nitrogen single, double, and triple bonds. Based on this information, what is the average pi-bond contribution to bond enthalpy?
single: 163kj/mol
double: 418kj/mol
triple: 941kj/mol
single: 163kj/mol
double: 418kj/mol
triple: 941kj/mol
Answers
Answered by
Jillian
941 - 418 = 523
418 - 163 = 255
523 + 255 = 778
778/2 = 389 kj/mol
(did it on mastering chemistry, answer was correct)
418 - 163 = 255
523 + 255 = 778
778/2 = 389 kj/mol
(did it on mastering chemistry, answer was correct)
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