To solve for "a" in the equation log2(a+5) = 3, we need to eliminate the logarithm by rewriting it in exponential form.
The logarithmic equation loga(b) = c can be rewritten in exponential form as:
a^c = b
Applying this to the given equation, we get:
2^3 = a + 5
Solving the exponentiation:
a + 5 = 8
Subtracting 5 from both sides:
a = 3
Therefore, the solution to the equation log2(a+5) = 3 is a = 3.
log2(a+5)=3
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