lim (lnx)^1/x
take the antilog
(e^x)^(1/x)=e^1=e
take the ln...
lim= 1
Find
a) lim (ln x)^1/x
x->infinity
b) lim (x-1)^lnx
x->1+
1 answer
a) lim (ln x)^1/x
x->infinity
b) lim (x-1)^lnx
x->1+
1 answer