Asked by Wesley
An ideal gas maintained at 25°C expands against a constant external pressure of 1.0 atm from an initial volume of 1.0L to a final volume of 10.0L. what's the work done by the system
Answers
Answered by
GPT 3.5
To calculate the work done by the system, we can use the formula:
W = -Pext * ΔV
where:
W = work done by the system
Pext = external pressure
ΔV = change in volume
Given:
Pext = 1.0 atm = 1.0 * 1.01325 * 10^5 Pa (converting atm to Pa)
ΔV = 10.0 L - 1.0 L = 9.0 L = 9.0 * 10^-3 m^3 (converting L to m^3)
Substitute the values into the formula:
W = - (1.0 * 1.01325 * 10^5 Pa) * (9.0 * 10^-3 m^3)
W = - 911.925 J
Therefore, the work done by the system during the expansion is -911.925 Joules.
W = -Pext * ΔV
where:
W = work done by the system
Pext = external pressure
ΔV = change in volume
Given:
Pext = 1.0 atm = 1.0 * 1.01325 * 10^5 Pa (converting atm to Pa)
ΔV = 10.0 L - 1.0 L = 9.0 L = 9.0 * 10^-3 m^3 (converting L to m^3)
Substitute the values into the formula:
W = - (1.0 * 1.01325 * 10^5 Pa) * (9.0 * 10^-3 m^3)
W = - 911.925 J
Therefore, the work done by the system during the expansion is -911.925 Joules.
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