Question

(5x^3-6x^2+8)/(x-4).

(4)

5 -6 8

5 14 72


For the remainder I divided 72/4 for 18. So the whole answer would be 5x^3+14x^2+18. But the book's answer is 5x^2+14x56+232/(x-4). Where did these numbers come from and where did I mess up?

Answer 1

Don't know if you read my reply to your previous post, where you made a similar error.
This time you forgot the allowance for a 0x term

(4)
5 -6 0 8

etc.