Question
(4x^3-9x+8x^2-18)/(x+2)-use synthetic division to divide. I set it up like this (pretend the parentheses are the synthetic division box).
(-2)
4 8 -27
4 0 -27.
For remainders, according to my book, we're supposed to divide the remainder by the divisor. So it would be -27/-2. Yet my book says there is no remainder. It says the answer is 4x^2-9. How did it get this?
(-2)
4 8 -27
4 0 -27.
For remainders, according to my book, we're supposed to divide the remainder by the divisor. So it would be -27/-2. Yet my book says there is no remainder. It says the answer is 4x^2-9. How did it get this?
Answers
Well Jeremiah, it's as simple as your forgetting the -9x term
try
(-2)
4 8 -9 -18
I get 4 0 -9 0
try
(-2)
4 8 -9 -18
I get 4 0 -9 0
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