Asked by Mia

A person holds an object of mass m = 4.2 kg on the palm of the hand with the arm stretched. Use the torque equilibrium equation to determine the magnitude of the force F exerted by the biceps muscle when a = 25 cm, b = (0.15 · a), and the angle θ = 75°. Neglect the weight of the lower arm

Answers

Answered by Anna
(a+b)(Fg)-b(Fcosθ) = 0
-->solve for F

Have you done #1 or #3 of the assignment? If you have, please help!
Answered by Mia
No but I am going crazy trying to do the calculations! Grr...wish I had more time to review before doing this h/w!

Thanks though. If I figure it out i'll post back here, ok
Answered by Karina
Hey Anna, can you break that down. I'm so confused!
Answered by Mia
Fg in the eqn she gave is mg...
Answered by Mia
Did any of you guys find 1 or 3?
Answered by Anna
So, basically i wrote down the torque equilibrium equation where torque equals 0 and the point of reference being the one shown in the diagram. The distance from the point of reference to where Fg is applied is a PLUS b since a is just the distance from the point where F is applied...NOT from the point of reference. The signs you can find using the right-hand rule..i used positive as counterclockwise..so torque is pointing towards you.
Answered by Mia
Anna if u are having trouble with number 3, have a look at Ex5.2 it will help.
Answered by Karina
these are the steps to do number 3. i still have yet to try it though:

first you need all the euations of the forces

so horizontal and vertcal

then you need torque

so once you hv your torque youll hv lots of L

you should factor that out

nd solve for T

then sub T into the horizontal forcees equation

nd solve for Rx

And for Question 2 are we supposed to convert cm to m and when we find b, there's no given units so am i supposed to just multiply it with a and it automatically becomes the same unit as a?
Answered by Anna
the units are given.. it's cm throughout..you don't have to convert because the units for l get canceled out in the end anyways

i got an answer around 3000 for #3? Anyone else get something similar?
Answered by Karina
yep, it's supposed to be a huge number for #3
Answered by Karina
i got around 4000s. Hey for question 2 is it supposed to be a tremendous number as well. I got like 4450
Answered by Ann
Did anyone figured out #1?
Answered by Anna
No! I've tried multiple ways to do it.. and yet still not getting the right answer. I think I'm messing up my coordiante system and the angles for the forces..
Answered by Karina
Question #1

T(l1)cos30 + Warm(l2)cos30 - WM(l3)cos30
solve for T
Answered by Anna
time's up..lol

Thanks guys!
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