A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number. (1 point) Responses 1,873 square centimeters 1,873 square centimeters 2,015 square centimeters 2,015 square centimeters 2,154 square centimeters 2,154 square centimeters 123,252 square centimeters

1 answer

To find the amount of wrapping paper needed to wrap a triangular prism, you need to calculate the surface area of all the faces.

The formula for finding the surface area of a triangular prism is:
2*(base area) + (perimeter of base)*(height)

Given that the container is a triangular prism, we need to know the base area, base perimeter, and the height.

Let's assume the base of the triangular prism is an equilateral triangle with side length 10 cm and height 15 cm.

Base area = (sqrt(3)/4)*(side length)^2
base area = (sqrt(3)/4)*(10)^2 = 25 sqrt(3) cm^2

Base perimeter = 3*side length = 3*10 = 30 cm

Now, calculate the surface area of the triangular prism:
2*(base area) + (perimeter of base)*(height)
= 2*(25 sqrt(3)) + 30*15
= 50 sqrt(3) + 450
≈ 522 cm^2

Rounded to the nearest whole number, the amount of wrapping paper needed to wrap the toy is 522 square centimeters. (Answer not provided in the options)