Question
Maya has some dimes and some quarters. She has a maximum of 21 coins worth no less than $3.30 combined. If Maya has 8 dimes, determine all possible values for the number of quarters that she could have.
Answers
GPT 3.5
Let's assume Maya has x quarters.
The value of x quarters is 0.25x dollars.
The value of 8 dimes is 0.10 * 8 = 0.80 dollars.
Therefore, the total value of Maya's coins is 0.25x + 0.80 dollars.
We know that the total value of the coins is no less than $3.30, so we have the inequality:
0.25x + 0.80 ≥ 3.30
0.25x ≥ 2.50
x ≥ 10
Since Maya can have a maximum of 21 coins, and we already know she has 8 dimes, the maximum number of quarters she could have is:
21 - 8 = 13 quarters
Therefore, the possible values for the number of quarters that Maya could have are 10, 11, 12, or 13 quarters.
The value of x quarters is 0.25x dollars.
The value of 8 dimes is 0.10 * 8 = 0.80 dollars.
Therefore, the total value of Maya's coins is 0.25x + 0.80 dollars.
We know that the total value of the coins is no less than $3.30, so we have the inequality:
0.25x + 0.80 ≥ 3.30
0.25x ≥ 2.50
x ≥ 10
Since Maya can have a maximum of 21 coins, and we already know she has 8 dimes, the maximum number of quarters she could have is:
21 - 8 = 13 quarters
Therefore, the possible values for the number of quarters that Maya could have are 10, 11, 12, or 13 quarters.