To find the equation of the line that passes through the point (-4,0) and is parallel to the line 5x - 4y = 20, we first need to find the slope of the given line.
The equation of the given line is 5x - 4y = 20. We need to rewrite it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
5x - 4y = 20
-4y = -5x + 20
y = (5/4)x - 5
The slope of this line is 5/4.
Since the line that passes through (-4,0) is parallel to the given line, it will have the same slope of 5/4.
Now that we have the slope, we can use the point-slope form of an equation of a line:
y - y1 = m(x - x1)
where (x1, y1) = (-4,0) and m = 5/4
y - 0 = (5/4)(x + 4)
y = (5/4)x + 5
Therefore, the equation of the line passing through (-4,0) and parallel to the given line is y = (5/4)x + 5.
What is an equation of the line that passes through the point left bracket, minus, 4, comma, 0, right bracket(−4,0) and is parallel to the line 5, x, minus, 4, y, equals, 205x−4y=20?
1 answer