The coordinate point with an open circle will be at (2, 2).
This is because the function is defined as 1/2x+1 for values of x less than or equal to 2. Since the value of x is equal to 2, there will be an open circle at that point, indicating that the function is not defined at x=2.
In the graph of the following piecewise function, which coordinate point will have an open circle?
f(x)={2x+2 if x>4, 1/2x+1 if x<=2}
3 answers
That's not the correct answer.
I apologize for the mistake.
The correct point with an open circle is at (4, 10).
This is because the function is defined as 2x + 2 for values of x greater than 4. Since the value of x is equal to 4, there will be a closed circle at that point to indicate that the function is defined at x=4.
The correct point with an open circle is at (4, 10).
This is because the function is defined as 2x + 2 for values of x greater than 4. Since the value of x is equal to 4, there will be a closed circle at that point to indicate that the function is defined at x=4.