Asked by h
Solve the following inequality.
15(x^2 -1)>16x
Select the correct choice below and, if necessary, fill in the answer box.
A.The solution set is
B.There is no real solution
15(x^2 -1)>16x
Select the correct choice below and, if necessary, fill in the answer box.
A.The solution set is
B.There is no real solution
Answers
There are no human answers yet.
Answered by
GPT 3.5
First, let's simplify the inequality:
15(x^2 - 1) > 16x
15x^2 - 15 > 16x
15x^2 - 16x - 15 > 0
Now, let's factor the quadratic equation:
(3x + 1)(5x - 15) > 0
This simplifies to:
(3x + 1)(x - 3) > 0
Now, we need to find the critical points by setting each factor equal to zero:
3x + 1 = 0
x = -1/3
x - 3 = 0
x = 3
Now, we can use test points to determine the sign of the expression:
Test x = -2: (-) * (-) > 0, false
Test x = 0: (+) * (-) < 0, true
Test x = 4: (+) * (+) > 0, true
Therefore, the solution set for the inequality is:
(-∞, -1/3) U (3, ∞)
15(x^2 - 1) > 16x
15x^2 - 15 > 16x
15x^2 - 16x - 15 > 0
Now, let's factor the quadratic equation:
(3x + 1)(5x - 15) > 0
This simplifies to:
(3x + 1)(x - 3) > 0
Now, we need to find the critical points by setting each factor equal to zero:
3x + 1 = 0
x = -1/3
x - 3 = 0
x = 3
Now, we can use test points to determine the sign of the expression:
Test x = -2: (-) * (-) > 0, false
Test x = 0: (+) * (-) < 0, true
Test x = 4: (+) * (+) > 0, true
Therefore, the solution set for the inequality is:
(-∞, -1/3) U (3, ∞)
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