solve the system of equations: 8x-3y=-22 , y=10+4x

Answer 1

First, substitute the second equation into the first equation:

8x - 3(10 + 4x) = -22

Simplify the equation:

8x - 30 - 12x = -22
-4x - 30 = -22
-4x = 8
x = -2

Now substitute x = -2 into the second equation to solve for y:

y = 10 + 4(-2)
y = 10 - 8
y = 2

Therefore, the solution to the system of equations is x = -2 and y = 2.